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7500=d^2+520d
We move all terms to the left:
7500-(d^2+520d)=0
We get rid of parentheses
-d^2-520d+7500=0
We add all the numbers together, and all the variables
-1d^2-520d+7500=0
a = -1; b = -520; c = +7500;
Δ = b2-4ac
Δ = -5202-4·(-1)·7500
Δ = 300400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{300400}=\sqrt{400*751}=\sqrt{400}*\sqrt{751}=20\sqrt{751}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-520)-20\sqrt{751}}{2*-1}=\frac{520-20\sqrt{751}}{-2} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-520)+20\sqrt{751}}{2*-1}=\frac{520+20\sqrt{751}}{-2} $
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